v/v^2-2v-3-4/v+1

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Solution for v/v^2-2v-3-4/v+1 equation: 


D( v )

v = 0

v^2 = 0

v = 0

v = 0

v^2 = 0

v^2 = 0

1*v^2 = 0 // : 1

v^2 = 0

v = 0

v in (-oo:0) U (0:+oo)

v/(v^2)-(2*v)-(4/v)-3+1 = 0

v/(v^2)-2*v-4*v^-1-3+1 = 0

-2*v^1-3*v^-1-2*v^0 = 0

(-2*v^2-2*v^1-3*v^0)/(v^1) = 0 // * v^2

v^1*(-2*v^2-2*v^1-3*v^0) = 0

v^1

-2*v^2-2*v-3 = 0

-2*v^2-2*v-3 = 0

DELTA = (-2)^2-(-3*(-2)*4)

DELTA = -20

DELTA < 0

v in { } 

v belongs to the empty set

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